How Do You Win At Roulette Every Time
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Since there is no skill in roulette possible (you are not playing against other humans), I guess no roulette related articles should be in this section? Almost every roulette player relies on some sort of `system`, whether it's a number/sequence system, a wagering/money management system, or a hybrid of both. What exactly offends you about his. Using the Martingale System The most effective way of using the Martingale is to only bet on even-money outside bets – 1-18, 19-36, Red, Black, Even, and Odd. They have the maximum odds of winning (almost 50%), but the lowest payout of all – 1:1. This means you win the same amount of money you bet for the spin. Confirmation That Roulette Can Be Beaten – how to win at roulette every time A sheltered roulette technique is vital, yet they can not generally be known as a basic roulette framework. You’d feel that on the off chance that somebody could beat roulette, that it would stand out as truly newsworthy and they’d win the Nobel Prize. You can’t win at roulette on every spin – that’s patently impossible. The only person who would ask this question doesn’t understand how roulette works. Having read this post (and some of my other posts about roulette), you already know how roulette works, so you won’t even worry about trying to win at roulette on every spin.
How To Win Roulette Every Time In Casino
why is it impossible to win at roulette? The basic line is that there are 37 numbers on the field (0-36) and payments are paid 36 to 1. So, every time you bet in, statistically, you are losing 2,7% from the betting amount (even if you have won in the current spin). If you want to check our mathematical explanations, read further.Why cannot you succeed in roulette via using strategies?
Let's consider all possible common bets in roulette as the mathematical proof of the impossibility to win in roulette and determine their ME (Mathematical expectation) result.
In the general case, I of any bet in roulette can be calculated using the classical formula (1):
, (1)- Where is xi– event I,
- Pi– The probability of the event I,
- К – The total number of events forming a complete group.
The mathematical expectation of the European version:
The formula (1) for ME of any bets on 'European roulette' can be converted taking into the full probability, not collaborative events, that is Pwin.+ Ploss.=1, to the view with the game for N sectors (rooms), is equal to:... (2)
Since the probability of winning Pwin in 'European roulette', while you are playing for N sectors (rooms), is equal to:
, that finally, we obtain the expression for ME for ANY bet in 'European roulette', when you are playing for N sectors (rooms), is equal to:... (3)Let's calculate ME for each 'simple' (basic) bet in 'European roulette' (a wheel with one zero). The result of ME calculation for average basic bets is presented in table 1.
The mathematical expectation for the bets:
Table 1. Calculation of ME for 'simple' bets.
№ | «Simple» bet | Winning | Loss | Calculation МО, у.е. | |
Payout | Probability | Probability | |||
1. | Straight-Up | 35:1 | 1/37 | 36/37 | =35×1/37-36/37= -1/37 |
2. | Split | 17:1 | 2/37 | 35/37 | =17×2/37-35/37= -1/37 |
3. | Street | 11:1 | 3/37 | 34/37 | =11×3/37-34/37= -1/37 |
4. | Corner | 8:1 | 4/37 | 33/37 | =8×4/37-33/37= -1/37 |
5. | Six Line | 5:1 | 6/37 | 31/37 | =5×6/37-31/37= -1/37 |
6. | Column & Dozens | 2:1 | 12/37 | 25/37 | =2×12/37-25/37= -1/37 |
7. | Even Chance | 1:1 | 18/37 | 19/37 | =1×18/37-19/37= -1/37 |
As can we see from the table – ME is exactly equal to the value obtained by the formula (3). Let's sum up the results.
The player always loses even when he wins
If the gambler is playing at 'European roulette', (no matter where and how much he puts), he ALWAYS loses 1/37 part of the bet (bets). At the same ME of the game, it is not dependent on the outcome of the spin; that is, the player loses even when he wins. Or in other words, the player ALWAYS loses when he makes a bet at 'European Roulette' regardless of the outcome of the current spin.Using the strategies of the bets:
For the mathematical proof of the winning's impossibility at 'European roulette' or 'American Roulette,' it is enough to expand any betting strategy on the 'basic' bet. As ME result of all bets is negative and equals -1/37 the size of the stake, then the total expectation of the game result will be negative and equal -1/37. The sum of all bets made by the player or -1/37 from the value of the average stake multiplied by the number of spins played by a gambler.
Assessing the ME of any strategy is enough to determine the value of the average bet while you are playing according to this strategy and taking into consideration all the rules of the transition from bet to bet, and multiplying the result by -1/37. The value of the average bet and sum of all of the bets are positive values; therefore ME is always less than zero, that is ME£0 and less than ME£-1/37 if used the progression because the average rate is bigger than 1.
Dispersion
Let's calculate the variance for any bet in 'European roulette', depending on how many sectors N (rooms) puts the gambler. Use the variance to determine the optimal Bank Kelly criterion for playing 'European roulette'.
Information
Bank on Kelly's criterion shows what should be the gambler's bank to the total balance of all games aspired to infinity.
In the general case, the variance of the player who is playing at the 'European roulette' in N sectors (rooms) can be calculated by the expression:
. (4)The formula (4) for the variance D of any bets on the 'European roulette' can be converted taking into the full probability, not joint events, that is Pwin.+ Ploss.=1, to the mind:
. (5)Since the probability of winning Pwin in the 'European Roulette' while you are playing for N sectors (rooms) is equal to:
, finally, we get the expression for the dispersion D of any bet at the 'European roulette' when you are playing for N sectors (rooms), is:. (6)The magnitude of dispersion D has a positive value throughout the range of games in N sectors. That is an important detail.
Where it is possible to calculate the required bank for the game at 'European roulette' using Kelly's criterion:
. (7)Using the expressions (3) and (6), we finally obtain the expression:
(8).The formula (8) shows that the optimal amount of the bank, according to Kelly's criterion for playing at 'European Roulette' is a negative value.
Conclusion:
If the optimal value of the gambler's bank following Kelly's criterion is negative, then playing at 'European roulette' is generally not necessary, since the overall result of the balance of all players` games approach to zero, or the player has to lose all his money during the long game.
To assess the 'attractiveness' of the gambling, you can use generalised criteria, which is obtained as the ratio of required the gambler's bank following Kelly's criterion to the mathematical expectation of the game result that is:
(9).This expression (9) can be understood that the smaller size of the gambler's bank at the mathematical expectation, the 'better' will be a game for the player. This optimal criterion can be interpreted as the criteria of minimal specific player's bank per unit of profit from the game.
How Do You Win At Roulette Every Time Win
The optimal criteria of the Кoptima game can only be used for evaluation of games with a positive expectation! If the game has a negative MT, it will not attract the attention of the gamblers. For 'European roulette' MT -1/37, that is less than zero, so 'European roulette' as the game is not 'attractive' for gamblers. That is why it is impossible to win in roulette, regardless of which betting strategies and tactics selection of items you use.
Note: the formula (3), (5) and (8) can be obtained for 'American roulette' with two sectors of zero: 0 and 00.
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How To Win At American Roulette Every Time
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